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2. SELECT * FROM pracownicy WHERE data_zatrudnienia >= '2012-03-1'
3. SELECT imie,nazwisko FROM pracownicy WHERE imie LIKE 'p%'
4. SELECT DISTINCT nazwisko FROM pracownicy
5. SELECT nazwisko FROM pracownicy WHERE LENGTH(nazwisko) > 6
6. SELECT UPPER(CONCAT(LEFT(imie,1),nazwisko)) AS 'Login' FROM pracownicy
7. SELECT imie, nazwisko, nazwaOddzialu FROM pracownicy INNER JOIN oddzialy ON pracownicy.oddzial = oddzialy.id_oddzialu
8. SELECT DISTINCT nazwaOddzialu FROM oddzialy LEFT OUTER JOIN pracownicy ON pracownicy.oddzial = oddzialy.id_oddzialu WHERE pracownicy.id_pracownika IS NULL
9. SELECT imie, nazwisko, nazwaOddzialu, nazwaMiasta FROM pracownicy LEFT JOIN oddzialy ON pracownicy.oddzial = oddzialy.id_oddzialu LEFT JOIN miasta ON oddzialy.miastoID=miasta.id_miasta
10. SELECT COUNT(id_pracownika) AS 'Liczba pracwonikow bez drugiego imienia' FROM pracownicy WHERE drugie_imie IS NULL
11. SELECT SUM(wynagrodzenie) * 12 AS 'Roczne wydatki na pensje' FROM pracownicy
12. SELECT MIN(LENGTH(imie)) AS 'Liczba liter najkrotszego imienia' FROM pracownicy
13. SELECT COUNT(id_pracownika) AS "Ilosc pracownikow", nazwaOddzialu FROM pracownicy INNER JOIN oddzialy ON pracownicy.oddzial = oddzialy.id_oddzialu GROUP BY nazwaOddzialu
14. SELECT YEAR(data_urodzenia) AS 'Data urodzenia', COUNT(YEAR(data_urodzenia)) AS 'Ile osob' FROM pracownicy GROUP BY YEAR (data_urodzenia)
15. kartka
16. SELECT imie, nazwisko FROM pracownicy WHERE wynagrodzenie = (SELECT MAX(wynagrodzenie) FROM pracownicy)
17. SELECT * FROM pracownicy WHERE data_urodzenia = (SELECT MAX(data_urodzenia) FROM pracownicy)
18. SELECT imie, nazwisko FROM pracownicy WHERE wynagrodzenie = (SELECT wynagrodzenie - 200 FROM pracownicy INNER JOIN oddzialy ON pracownicy.id_pracownika = oddzialy.kierownikId WHERE oddzialy.nazwaOddzialu = 'IT')
19. SELECT SUM(cyfra) AS 'Suma cyfr od 9 do 7' FROM (SELECT 9 AS cyfra UNION SELECT 8 UNION SELECT 7) AS cyfry;
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