Notes

#include <iostream>
#include <string>
#include <windows.h>

using namespace std;

//Making structure
struct Date
{
int month, day, year;
};

//Array for days in month
const int monthDays[12] = { 31, 28, 31, 30, 31, 30,
31, 31, 30, 31, 30, 31 };

// This function counts number of leap years before the
// given date
int countLeapYears(Date day)
{
int years = day.year;

// Check if the current year needs to be considered
// for the count of leap years or not
if (day.month <= 2)
years--;

// An year is a leap year if it is a multiple of 4,
// multiple of 400 and not a multiple of 100.
return years / 4 - years / 100 + years / 400;
}

int main()
{
SYSTEMTIME ct;
GetLocalTime(&ct);
Date birth, current;
string name;
char response;
current.month = ct.wMonth;
current.day = ct.wDay;
current.year = ct.wYear;

cout << "This is my program 'Alive'. It will calculate the amount of days you have been alive.nTo start this program, please enter your name. ";
getline(cin, name);
cout << "nHello " << name << ", please enter the number of the month that you were born in: ";
cin >> birth.month;
cout << "nNow please enter the day of the month that you were born: ";
cin >> birth.day;
cout << "nFinally, please enter the year that you were born: ";
cin >> birth.year;

cout << "nYou were born on " << birth.month << "/" << birth.day << "/" << birth.year << ". Is that correct? Y/N ";
cin >> response;
if (response == 'Y' || response == 'y') {
cout << "nThe current date is " << current.month << "/" << current.day << "/" << current.year;

// This function returns number of days between two given
// dates
int getDifference(Date dt1, Date dt2);
{
// COUNT TOTAL NUMBER OF DAYS BEFORE FIRST DATE 'dt1'

// initialize count using years and day
long int n1 = dt1.year * 365 + dt1.day;

// Add days for months in given date
for (int i = 0; i<dt1.month - 1; i++)
n1 += monthDays[i];

// Since every leap year is of 366 days,
// Add a day for every leap year
n1 += countLeapYears(dt1);

// SIMILARLY, COUNT TOTAL NUMBER OF DAYS BEFORE 'dt2'

long int n2 = dt2.year * 365 + dt2.day;
for (int i = 0; i<dt2.month - 1; i++)
n2 += monthDays[i];
n2 += countLeapYears(dt2);

// return difference between two counts
return (n2 - n1);
}
cout << "Difference between two dates is " << getDifference(dt1, dt2);

return 0;
}

}
else if (response == 'N' || response == 'n') {
cout << "Please relaunch the program and try again.n";
}
return 0;
}