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0 / 1 pts
Your survey a population showing two alleles at the A gene. You find that allele A has frequency of 0.6, while allele a has frequency 0.4. Is this population obeying Hardy-Weinberg?
(A) Yes.
You Answered
(B) No.
Correct Answer
(C) I cannot tell from the information provided.
Question 2
1 / 1 pts
In population close to that in question 1, you see that genotype frequencies for the A gene all add up to one – they are: f(AA) = 0.4, f(Aa) = 0.2, f(aa) =0.4. Thus, you have assured that f(AA) + f(Aa) + f(aa) = 0.4 + 0.2 + 0.4 = 1. Is this neighboring population at Hardy-Weinberg Equilibrium?
(A) Yes.
Correct!
(B) No.
(C) I cannot tell from the information provided.
Question 3
1 / 1 pts
Imagine that your population is at Hardy Weinberg equilibrium. Further, imagine, in this two allele system, that the frequency of the A allele was 0.8. What is the frequency of the AA genotype and the Aa heterozygote, respectively?
(A) 0.32, 0.64
(B) 0.64, 0.34
(C) 0.68, 0.32
(D) 0.8, 0.2
Correct!
(E) 0.64, 0.32
Question 4
0 / 1 pts
You go survey a population of monkeys. You know nothing about the population, except that at the A gene there are two alleles, A and a. You see that the frequency of the AA genotype is 0.64, and the frequency of the aa genotype is 0.24.
What is the frequency of the Aa heterozygote?
(A) f(Aa) = 0.14
(B) f(Aa) = 0.8
(C) f(Aa) = 1.08
You Answered
(D) f(Aa) = 0.2
Correct Answer
(E) None of the above.
Question 5
0 / 1 pts
For that same population of monkeys: What is the frequency of the A allele, f(A)?
(A) f(A) = 0.8.
Correct Answer
(B) f(A) = 0.7.
You Answered
(C) f(A) = 0.78.
(D) f(A) = 0.88.
(E) The answer cannot be determined h others. Click here ...
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