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number?
2
3. Convert each of the following values to decimal.
a) 101011101
b) 111010
2
c) 101010101
d) 01011001
6
= 64
Largest 6bit unsigned binary number =
64
2
= 2
=2
5
= 2
= 2
8
+ 2
+ 2
4
8
+ 2
+ 2
6
+ 2
+ 2
3
6
+ 2
+ 2
4
+ 2
+ 2
1
4
+ 2
+ 2
3
+ 2
2
+ 2
=
58
2
+ 2
0
=
=
89
0
=
349
2
341
2
6
4
3
0
4.
Convert each of the following values to a 10bit signed magnitude binary value.
a) 47
10
=
0000101111
b) 243
=
1011110011
10
c) 23
10
=
1000000111
d) 177
=
0000110001
10
5. Convert the following numbers to hexadecimal.
a) 101011110010100011
2
= 0x
2BCA3
b) 1011010101010101001
2
= 0x
5AAA9
c) 01101001001010011001
2
= 0x
69299
d) 10101100101010
2
= 0x
2B2A
6. Convert each of the following hexadecimal numbers to binary.
a)ABCD
16
= 1010 1011 1100 1101 =
1010101111001101
b) 1DEF
16
= 0001 1101 1110 1111 =
0001110111101111
c) 86E5
16
= 1000 0110 1110 0101 =
1000011011100101
d) 923A
16
= 1001 0010 0011 1010 =
1001001000111010
7. Convert 5 d) and 6 b) to decimal numbers.
5d) 10101100101010
2
= 0B2A
16
= 0*(16^3) 11*(16^2) + 2*(16^1) + 10*(16^0) =
2858
6b) 0001110111101111
2
= 1DEF
16
= 1*(16^3) + 13*(16^2)+ 14*(16^1)+ 15*(16^0) =
7663
8. Convert each of the following decimal values to 8bit 2’s complement binary
a) 39
10
b) 127
=
00100111
10
=
10000001
c) 98
10
=
10011110
9. Convert 1101.0011011
2
to decimal.
3*2 + 2*2 + 1*0 + 1*0 + .5*0 + .25*0 + .125*1 + .0625*1 + .03125*0 + .015625*1 + .0078125*1
= 6 + 4 + .125 + .0626 + .015625 + .0078125 =
13.2109375
10 . Convert 217
10
to base 5 using the divisionremainder method
217 / 5 = 2
43 / 5 = 3
8 / 5 = 3
1 / 5 = 1
=
1332
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