Notes

A little formula to simplify the bear off in Backgammon
"I was finishing a backgammon game and had two pieces left, 1 on 4, and the other on 2. I rolled a 6, 3, and I thought the backgammon game was more than, but my opponent stated that I had to move my four piece to the 1 slot, then consider the two off with the six roll. She said I had to do this since I had the chance to move my piece, it's a backgammon rule! I have got $. riding on this, is it correct? What is the appropriate backgammon rule? http://www.takomascatter.com/improve-your-poker-with-affiliates/ Please respond!"

We have acquired numerous messages as the over 1 and decided to provide a useful formula for beginners. The formula is fairly easy:

"If the amount of the dice that you have rolled is equal or bigger than the quantity of the row* that your checker** is positioned you bear off. If the dice amount is smaller sized than the row amount you need to play that quantity by moving your checker in direction of rows with smaller sized quantity."

Row*: the room, the slot, the discipline. that you perform or location your checkers. 24 rows exist on the backgammon board.

Checker**: the stone, the piece. that you perform on the board. Every player has 15 checkers.

The formula may seem tough but do not be concerned, it is not, let me describe! To commence to bear off you ought to enter all your checkers into your house location and in your home region you have 6 rows. Let's place a number to every of these 6 rows. The very first one is "r1" which is also the row that your opponent's two checkers are positioned on the beginning of the game.

Then you have "r2", "r3", "r4", "r5" lined side by side and the last one is "r6" in which you location five checkers on the starting. Now you know that the row amount is a quantity among one and 6. Exact same of the dice quantity!

Now suppose that you have a single checker in row five and a single checker in row 2 (better is to use your actual backgammon board and simulate individuals prospects), and you have rolled a "6 + 3", 6 is larger than five and three is larger than two, and you bear off your two checkers!

Suppose you have 2 checkers in "r4" and one checker in "r1", you have rolled a "four + 3", you bear off a single checker from "r4" with your dice number four, and for dice amount 3 you need to move a single checker from "r4" to "r1".

You have 3 checkers in "r6" and 2 checkers in "r3", four checkers in "r2" and 3 checkers in "r1". You have rolled a "5 + 4". Regrettably you will move 2 checkers from "r6" to "r2" and "r1", and you can not bear any checker off.

You have three checkers in "r6", three in "r5", two in "r4", four in "r2" and three in "r1", and you have rolled a "double3", simply because your "r3" is empty you should move two checkers from "r6" to "r3" and bear 2 checkers off from "r3".

You have three checkers in "r3", four checkers in "r2" and five checkers in "r1", you have rolled a "five + four". You will bear 2 checkers off from "r3".

You have 2 checkers in "r6", 4 checkers in "r5", one checker in "r4", three checkers in "r3", 3 checkers in "r2" and two checkers in "r1". You have rolled a "double4". You will bear one checker off from "r4", move two checkers from "r6" to "r2" and one checker from "r5" to "r1". Only a single checker has been born off.

Possibly the worst place is when you have only two checkers remaining in "r2" and you roll one "one", for instance a "three + 1". Whilst 3 is bigger than "r2", one is smaller sized, and you will bear a single checker off but move the last 1 to "r1" and wait for the up coming hand. Identical for "2 + one" or "four + 1"
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