Notes

# Define a function that takes a sorted list and a target value as inputs
def binary_search(lst, target):
# Check if the list is empty
if not lst:
# Return -1 to indicate that the target value is not found
return -1
# Find the middle index of the list
mid = len(lst) // 2
# Compare the middle element with the target value
if lst[mid] == target:
# Return the middle index as the position of the target value
return mid
elif lst[mid] > target:
# Recursively search in the left half of the list
return binary_search(lst[:mid], target)
else:
# Recursively search in the right half of the list
# Add mid + 1 to adjust the index in the original list
return mid + 1 + binary_search(lst[mid + 1:], target)

# Test the function with some examples
lst = [2, 4, 6, 8, 10]
target = 6
print(binary_search(lst, target)) # Output: 2

lst = [1, 3, 5, 7, 9]
target = 4
print(binary_search(lst, target)) # Output: -1

lst = []
target = 2
print(binary_search(lst, target)) # Output: -1