Notes

Certainly! Here are the SQL queries for each of your requests:

1. Find workers with the same first name from the `Worker` table:

```sql
SELECT FirstName, COUNT(*) AS NameCount
FROM Worker
GROUP BY FirstName
HAVING COUNT(*) > 1;
```

2. Retrieve Worker ID, Working Title, Department, and Joining Date from the `Worker` and `Title` tables:

```sql
SELECT W.WorkerID, T.WorkingTitle, W.Department, W.JoiningDate
FROM Worker W
INNER JOIN Title T ON W.WorkerID = T.WorkerID;
```

3. Find the worker who received the highest bonus in the shortest time:

```sql
SELECT B.WorkerID, MAX(B.BonusAmount) AS HighestBonus
FROM Bonus B
INNER JOIN Worker W ON B.WorkerID = W.WorkerID
GROUP BY B.WorkerID
ORDER BY MIN(B.BonusDate - W.JoiningDate) ASC
LIMIT 1;
```

4. Calculate the total bonus amount paid by the company:

```sql
SELECT SUM(BonusAmount) AS TotalBonusAmount
FROM Bonus;
```

5. Calculate the duration from an employee's joining date to when they received a bonus:

```sql
SELECT W.WorkerID, DATEDIFF(MONTH, W.JoiningDate, MIN(B.BonusDate)) AS DurationToBonus
FROM Worker W
LEFT JOIN Bonus B ON W.WorkerID = B.WorkerID
GROUP BY W.WorkerID, W.JoiningDate;
```

6. Sort the Worker table by their joining dates:

```sql
SELECT * FROM Worker
ORDER BY JoiningDate;
```

7. Find how many workers have not received a bonus with their Worker ID, first name, salary, and department:

```sql
SELECT W.WorkerID, W.FirstName, W.Salary, W.Department
FROM Worker W
LEFT JOIN Bonus B ON W.WorkerID = B.WorkerID
WHERE B.WorkerID IS NULL;
```

8. Sort the Worker table by department based on the highest bonus received:

```sql
SELECT W.WorkerID, W.Department, MAX(B.BonusAmount) AS HighestBonus
FROM Worker W
LEFT JOIN Bonus B ON W.WorkerID = B.WorkerID
GROUP BY W.WorkerID, W.Department
ORDER BY HighestBonus DESC, W.Department;
```

9. Find workers whose first names start with 'S':

```sql
SELECT * FROM Worker
WHERE FirstName LIKE 'S%';
```

10. Update a new employee in the Worker and Bonus tables:

```sql
-- Insert the new worker into the Worker table
INSERT INTO Worker (WorkerID, FirstName, LastName, Salary, JoiningDate, Department)
VALUES (7, 'New', 'Employee', 60000, '2023-09-01', 'New Department');

-- Insert a bonus record for the new worker
INSERT INTO Bonus (WorkerID, BonusDate, BonusAmount)
VALUES (7, '2023-09-15', 2500);
```

Please note that these queries are based on the assumption that the tables already exist and have the specified columns.