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The molarity of NaCl was calculated by dividing the mass of NaCl (50 g) by its molar mass (58.8 g/mol), resulting in 0.8547 moles of NaCl. To convert moles to molarity, the equation molarity = moles/liters was used, with the calculated value of moles and the volume of the solution (10 mL). This resulted in a molarity of 85.47 M.
The density of the solution was calculated using the equation density = grams/mL, with the mass of NaCl (50 g) and the volume of the solution (10 mL). This resulted in a density of 5.0 g/mL.
Substituting the calculated values of density and molarity into the equation for the relationship between density and molarity (density = mMolarity + b), the slope of the equation was determined. The slope represents the relationship between density and molarity and was found to be equal to the density of the solution divided by its molarity. Substituting the calculated values, the slope equation was (5.0 g/mL)/(85.47M), which resulted in a slope value of 0.0585 g/mLM.
Since the slope value is identical to the constant m in the equation, the value of m was found to be 0.0585 g/mLM. The value of b was obtained by substituting all calculated values into the equation Density = mMolarity + b and solving for b. The value of b was found to be (5.0 g/mL) – (0.0585 g/mLM * 85.47 M), which resulted in a value of 1.0 g/mL.
In conclusion, the constants m and b in the equation that describes the relationship between the density and molarity of a solution were determined through the calculation of the density and molarity of a NaCl solution. The slope value, which is identical to the constant m, was found to be 0.0585 g/mLM, and the value of b was found to be 1.0 g/mL.
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