Notes

/**
* @param {character[][]} board
* @return {boolean}
*/
var isValidSudoku = function(board) {
// Sure
// So, I'm thinking we identify the edge cases, like no number must repeat along each array board[i], each row

// CASE 1: check if each row in board[i] is valid
// CASE 2: Check if every column is valid
const columns = []
const cells = []

for (var i = 0; i < board.length; i++) {
const nums = [] // store the numbers in every row as we iterate
for (var j = 0; board[i].length; j++) {
if (nums.includes(board[i][j])) return false;
if (columns[j].includes(board[i][j])) return false;

// My intuition is to mind the bottom-right total index of each cell and see if we can map it to the cell number
cells[0] => 2 x 2 = 4
cells[1] => 5 x 2 = 10
cells[2] => 8 x 2 = 16
cells[3] => 2 x 5 = 10
cells[4] => 5 x 5 = 25
cells[5] => 8 x 5 = 40
I'm not seeing an easy pattern
say again
Yes
I'm using the browser
I'll
if (i < 3 && j < 3)
cells[j].push(board[i][j % 3])


// I think they give an indication of which cell we are in
columns[j].push(board[i][j])
// I'm trying to get a way of identifying where each element belongs
nums.push(board[i][j])
}
}

// Except if we generate columns as we loop through the rows so that we just use the same funtion to see if there is any repetition

// CASE 3: group every 3 x 3 block and check if there is repetition
// Maybe we'll use an Object or array to generate a flat array as we loop through every 3 x i columns and row

};