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If the speed of the first train is mph faster than that of the second​ train, write an expression for the speed of the first train.
The speed of the first train plus the speed of the second train is
(x + 7.2) + x = 726.8
Now solve the equation. Remove the parentheses and combine like terms.
(x + 7.2) + x = 726.8
2x + 7.2 = 726.8
Subtract seven-point-two from both sides of the equation
726.8 - 7.2
2x = 719.6
Finally divide both sides by two to solve for x
2x/2 719.6/2
x = 359.8
the speed of the second train is 359.8
x + 7.2 = 359.8 + 7.2
367 MPH
(x + 6.9) + x = 719.1
2x + 6.9 = 719.1
2x + 6.9 - 6.9
719.1 - 6.9
2x = 712.2
2x/2 712.2/2
x = 356.1
the speed of the second train is 356.1
356.1 + 6.9
the speed of the first train is 363




Given that x equals the number of points Team Tackle​ scored, what is an expression for the number of points that Team Sack​ scored?
x -33
Translate the problem into an equation.
points Team Tackle scored plus points Team Sack scored is equal to total points
x + (x - 33) = 57
Now solve the equation. Combine the​ x-terms on the left side.
x + x - 33 = 57
2x - 33 = 57
Next add 33 to both sides of the equation to isolate the​ x-term on the left side.
2x - 33 + 33 = 57 + 33
2x = 90
​Finally, divide both sides by 2 to solve for x.
2x/2 90/2
x = 45
Since we let the number of points Team Tackle scored equal​ x, Team Tackle scored points. Team Sack has 33 less than​ that, 12 points.
x - 21
x + (x - 21) = 47
2x - 21 = 47
2x - 21 + 21
47 + 21
2x = 68
68/2
x = 34

p - 323 = 2819
p-323+323 = 2819+323
p = 3142

p - 330 = 2813
p-330+330 = 2813+330
p = 3,143

3+ 0.60x + 6.00 =36.00
0.60x + 9 = 36.00
subtract nine
0.60x + 9 - 9 = 36.00 - 9
0.60x = 27
divide by 0.60
27/0.60
x = 45

4 + 0.90x + 6.00 = 46.00
0.90x + 10 = 46.00
0.90x + 10 - 10 = 46.00 - 10
0.90x = 36
36/0.90
x = 40


     
 
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