Notes

the wind mill works on precept of converting
kinetic strength of the wind into mechanical power.
the Kinetic Energy of any particle is equal to the only half of its
mass instances the rectangular of its speed, or ½ mv2.
K.E =½ MV2. ………………….. (1)
K.E= kinetic energy
M = mass
V = velocity,
M is equal to extent extended by way of its density ρ of
air,
mass = ρ av …………………. (2)
substituting eqn (2) in eqn (1) we had were given,
k e = ½ ρ av3 watts
ρ = density of air (1.225 kg/m3)
a = l*b (squarem)
d = diameter of the blade
a = l*b
a = zero.three sq.
to be had wind energy pa = (½ ρ π d2 v3)/four
p = 1/8 ρ π d2 v3
trail 1
for pace 4.5m/s
pa = (½ ρ π d2 v3)/4
pa = (½*1.225*π*0.four*zero.four *4.fifty three)/four
pa = 7.1watt

trail 2
for pace 5.5m/s
pa = (½ ρ π d2 v3)/4
pa = (½*1.225*π*0.4*zero.4 *5.53)/four
pa = 15.1watt

trail 3
for speed 7.5m/s
pa = (½ ρ π d2 v3)/four
pa = (½*1.225*π*0.four*zero.4 *7.fifty three)/4
pa = 33 watt

path four
for pace 10m/s
pa = (½ ρ π d2 v3)/four
pa = (½*1.225*π*zero.four*0.four *103)/4
pa = 77watt