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Dear Student,
The equation used for this problem is as follows,
Real depth(d1)/Apparent depth(d2) = n2/n1 , n2 is the refractive index of the denser medium (water) and n1 is refractive index of the rarer medium (air).
Here the d2 is given as 1.5m and for the case when the object in denser medium is viewed from the rarer medium
d1>d2. So here d1>1.5 and can be estimated as.
d1 =n2×d2n1 , where n2= 4/3 and n1=1 substituting the values, we have
The real depth of tank, d1 = 2m.
Hence the solution is option (A).
I hope I solved your problem thoroughly.
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